After a thorough going over of the code, I’ve managed to get this one working. Although painfully slow, at least it works. In the future I will be looking at other algorithms which are much faster. I only remembered this one from a long time ago so I just thought I’d have a go on my own without any help with implementing it.
// File: generate.agc
// Created: 19-09-21
/*
Attempting to generate a maze using a decent algorithm.
Unfortunately this particular algorith is painfully slow,
but for the time being, it does work.
*/
type MAZE
seed as integer
wid as integer
hgt as integer
maze as integer[0,0]
endtype
function maze_get_odd_random(max as integer)
val = random(0, ((max - 2) / 2)) * 2 + 1
endfunction val
function maze_not_visited(obj ref as MAZE, xpos, ypos)
val = obj.maze[ypos, xpos]
endfunction val
/*
The width and height have to be even numbers.
NB: In AGK this means 0 to width (as even) for example
NOT 0 to width - 1
*/
function maze_gen(obj ref as MAZE, wid as integer, hgt as integer, seed as integer)
obj.seed = seed
SetRandomSeed(seed)
obj.wid = wid
obj.hgt = hgt
/*
Wierd way of assigning a multidimensional array
Assign the first dimensions length
And then assign the length of each separate part
ie.
a[0].length = 5 (giving a[0,4])
is not the same as
a[1].length = 10 (which gives a[1,9])
Also, AGK arrays end with the value assigned.
ie. length is 10 so the array goes from 0 to 10
instead of 0 to 9.
*/
obj.maze.length = hgt
for c = 0 to hgt
obj.maze[c].length = wid
for x = 0 to wid
obj.maze[c, x] = 1
next
next c
/*
If I remember correctly, I choose a random cell.
But, it has to be, erm, ODD or EVEN???
I will find out...
It has to be odd.
*/
currentx = maze_get_odd_random(wid)
currenty = maze_get_odd_random(hgt)
// set position to 0
obj.maze[currenty, currentx] = 0
done = 0
repeat
// iterations to run through (might increase)
for route = 0 to 63
/*
Basically direction is UP, DOWN, LEFT or RIGHT
*/
direction = random(0, 3)
select direction
case 0:
if currenty - 2 > 0
if maze_not_visited(obj, currentx, currenty - 2)
obj.maze[currenty - 2, currentx] = 0 // clear path
obj.maze[currenty - 1, currentx] = 0 // between
endif
dec currenty, 2
endif
endcase
case 1:
if currenty + 2 < hgt
if maze_not_visited(obj, currentx, currenty + 2)
obj.maze[currenty + 2, currentx] = 0
obj.maze[currenty + 1, currentx] = 0
endif
inc currenty, 2
endif
endcase
case 2:
if currentx - 2 > 0
if maze_not_visited(obj, currentx - 2, currenty)
obj.maze[currenty, currentx - 2] = 0
obj.maze[currenty, currentx - 1] = 0
endif
dec currentx, 2
endif
endcase
case 3:
if currentx + 2 < wid
if maze_not_visited(obj, currentx + 2, currenty)
obj.maze[currenty, currentx + 2] = 0
obj.maze[currenty, currentx + 1] = 0
endif
inc currentx, 2
endif
endcase
endselect
next
/*
Print this mazes iteration (just for testing)
*/
Print( ScreenFPS() )
maze_print(obj)
print("Calculating...")
sync()
/*
Check if maze is done (the silly bit)
*/
done = 0
for h = 1 to hgt - 1 step 2
for w = 1 to wid - 1 step 2
if obj.maze[h, w] = 1
done = 1
exit // quick exit if not done
endif
next
if done = 1 then exit
next
until done = 0
endfunction obj
function maze_print(obj ref as MAZE)
print (obj.wid)
print (obj.hgt)
//print (random(0, 2) - 1) // HUH
for h = 0 to obj.hgt
s as string = ""
for w = 0 to obj.wid
if obj.maze[h, w] = 1 then s = s + "#" else s = s + " "
next
print (s)
next
endfunction
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Can you be more specific about the content of your article? After reading it, I still have some doubts. Hope you can help me.
Thank you for your sharing. I am worried that I lack creative ideas. It is your article that makes me full of hope. Thank you. But, I have a question, can you help me?